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if (rules == null) return true; Range range = (Range) rules.get( range ); return range == null || range.isInRange((Comparable) value); } /** * Returns <code>false</code> if the provided value is a required * field and is blank or null; <code>true</code> otherwise. * @param key The name of the field to be validated * @param value The value to be validated * @return The result of the validation */ protected boolean validateRequired(String key, String value) { Map rules = (Map) validationMap.get(key); if (rules == null) return true; Boolean required = (Boolean) rules.get( required ); if (required == null) return true; boolean isRequired = required.booleanValue(); Boolean isBlank = (value == null || value.trim().equals( )); return !(isRequired && isBlank); } /** * Returns a Map containing the values from the provided * Java bean, keyed by field name. Entries having keys * that match any of the strings returned by * <code>keysToSkip()</code> will be removed. * * @param bean the Java bean from which to create the Map * @return a Map containing values from the provided bean */ protected Map mapRepresentation(Object bean, int mode) { String errorMsg = Unable to format values from bean: + bean; Map valueMap = null; // PropertyUtils.describe() uses Introspection to generate a Map // of values from its argument, keyed by field name. try { valueMap = PropertyUtils.describe(bean); } catch (IllegalAccessException iae) { throw new FormattingException(errorMsg, iae); } catch (InvocationTargetException ite) {

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Find the roots of the error locator polynomial This has a computation cost of 0 (pn) using the Chien search 4 Compute the error values, with a cost of 0 (p2) Thus, if p < n / 2 , the most expensive steps are computing the syndromes and finding the roots In remainder decoding, decoding takes place by computing remainders instead of syndromes; the remaining steps retain similar complexity This results in potentially faster decoding Furthermore,as we demonstrate,it is possible to find the error locator polynomial using a highly-parallelizablealgorithm The general outline for the new decoding algorithm is as follows: 1 Compute the remainder polynomial r ( x ) = R ( x ) mod g(x), with complexity O ( n ) (using very simple hardware) 2 Compute an error locator polynomial W(x) and an associated polynomial N ( x ) The complexity is 0 (p2).

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Architectures exist for parallel computation 3 Find the roots of the error locator polynomial, complexity 0 ( p n ) 4 Compute the error values, complexity O(p2)..

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The top of an accretionary prism is de ned by a relatively abrupt decrease in slope called the trench slope break Between this break and the island arc, a forearc basin may develop, which is then lled with sediments derived from erosion of the volcanic arc and its substrate This basin is a region of tranquil sedimentation where at-lying units cover the oldest thrust slices in the wedge Seaward of the forearc basin, on the trench slope, small pockets of sediment also accumulate on top of old thrust slices (Fig 920b) The ages of these old slices, and their distance from the toe of the prism, provide a means of estimating lateral growth rates For example, drilling at sites 1175 and 1176 in the Nankai prism has shown that trench slope sands unconformably overlie thrust slices that may be as young as 1 or 2 Ma (Moore et al.

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, 2001; Underwood et al, 2003) Assuming steady state seaward growth, the distance of these thrust slices from the deformation front implies lateral growth rates as high as 40 km over the last 1 to 2 Myr In comparison, the Middle America accretionary prism off the coast of Mexico has grown 23 km in width over the past 10 Myr (Moore et al, 1982) and the eastern Aleutian accretionary prism has grown 20 km in 3 Myr (von Huene et al, 1998) Erosion of the trench slope and other landward material commonly results in slump deposits and debris ows that can carry material as far as the trench, where it gets offscraped and recycled back into the wedge.

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